From a139772e7751017d66d82877b3666d58df7ef00b Mon Sep 17 00:00:00 2001 From: Corey Farwell Date: Sun, 24 Jul 2016 22:10:36 -0400 Subject: [PATCH] Rewrite/expansion of `slice::split` doc examples. --- src/libcollections/slice.rs | 37 +++++++++++++++++++++++++++++++------ 1 file changed, 31 insertions(+), 6 deletions(-) diff --git a/src/libcollections/slice.rs b/src/libcollections/slice.rs index 1f8eea56fc6..ccef6c02f9d 100644 --- a/src/libcollections/slice.rs +++ b/src/libcollections/slice.rs @@ -691,15 +691,40 @@ pub fn split_at_mut(&mut self, mid: usize) -> (&mut [T], &mut [T]) { /// /// # Examples /// - /// Print the slice split by numbers divisible by 3 (i.e. `[10, 40]`, - /// `[20]`, `[50]`): + /// ``` + /// let slice = [10, 40, 33, 20]; + /// let mut iter = slice.split(|num| num % 3 == 0); /// + /// assert_eq!(iter.next().unwrap(), &[10, 40]); + /// assert_eq!(iter.next().unwrap(), &[20]); + /// assert!(iter.next().is_none()); /// ``` - /// let v = [10, 40, 30, 20, 60, 50]; /// - /// for group in v.split(|num| *num % 3 == 0) { - /// println!("{:?}", group); - /// } + /// If the first element is matched, an empty slice will be the first item + /// returned by the iterator. Similarly, if the last element in the slice + /// is matched, an empty slice will be the last item returned by the + /// iterator: + /// + /// ``` + /// let slice = [10, 40, 33]; + /// let mut iter = slice.split(|num| num % 3 == 0); + /// + /// assert_eq!(iter.next().unwrap(), &[10, 40]); + /// assert_eq!(iter.next().unwrap(), &[]); + /// assert!(iter.next().is_none()); + /// ``` + /// + /// If two matched elements are directly adjacent, an empty slice will be + /// present between them: + /// + /// ``` + /// let slice = [10, 6, 33, 20]; + /// let mut iter = slice.split(|num| num % 3 == 0); + /// + /// assert_eq!(iter.next().unwrap(), &[10]); + /// assert_eq!(iter.next().unwrap(), &[]); + /// assert_eq!(iter.next().unwrap(), &[20]); + /// assert!(iter.next().is_none()); /// ``` #[stable(feature = "rust1", since = "1.0.0")] #[inline] -- 2.44.0