error: you seem to be trying to use `match` for destructuring a single pattern. Consider using `if let` --> $DIR/single_match.rs:8:5 | LL | / match x { LL | | Some(y) => { LL | | println!("{:?}", y); LL | | }, LL | | _ => (), LL | | }; | |_____^ | = note: `-D clippy::single-match` implied by `-D warnings` help: try this | LL | if let Some(y) = x { LL | println!("{:?}", y); LL | }; | error: you seem to be trying to use `match` for destructuring a single pattern. Consider using `if let` --> $DIR/single_match.rs:16:5 | LL | / match x { LL | | // Note the missing block braces. LL | | // We suggest `if let Some(y) = x { .. }` because the macro LL | | // is expanded before we can do anything. LL | | Some(y) => println!("{:?}", y), LL | | _ => (), LL | | } | |_____^ help: try this: `if let Some(y) = x { println!("{:?}", y) }` error: you seem to be trying to use `match` for destructuring a single pattern. Consider using `if let` --> $DIR/single_match.rs:25:5 | LL | / match z { LL | | (2..=3, 7..=9) => dummy(), LL | | _ => {}, LL | | }; | |_____^ help: try this: `if let (2..=3, 7..=9) = z { dummy() }` error: you seem to be trying to use `match` for destructuring a single pattern. Consider using `if let` --> $DIR/single_match.rs:54:5 | LL | / match x { LL | | Some(y) => dummy(), LL | | None => (), LL | | }; | |_____^ help: try this: `if let Some(y) = x { dummy() }` error: you seem to be trying to use `match` for destructuring a single pattern. Consider using `if let` --> $DIR/single_match.rs:59:5 | LL | / match y { LL | | Ok(y) => dummy(), LL | | Err(..) => (), LL | | }; | |_____^ help: try this: `if let Ok(y) = y { dummy() }` error: you seem to be trying to use `match` for destructuring a single pattern. Consider using `if let` --> $DIR/single_match.rs:66:5 | LL | / match c { LL | | Cow::Borrowed(..) => dummy(), LL | | Cow::Owned(..) => (), LL | | }; | |_____^ help: try this: `if let Cow::Borrowed(..) = c { dummy() }` error: you seem to be trying to use `match` for an equality check. Consider using `if` --> $DIR/single_match.rs:87:5 | LL | / match x { LL | | "test" => println!(), LL | | _ => (), LL | | } | |_____^ help: try this: `if x == "test" { println!() }` error: you seem to be trying to use `match` for an equality check. Consider using `if` --> $DIR/single_match.rs:100:5 | LL | / match x { LL | | Foo::A => println!(), LL | | _ => (), LL | | } | |_____^ help: try this: `if x == Foo::A { println!() }` error: you seem to be trying to use `match` for an equality check. Consider using `if` --> $DIR/single_match.rs:106:5 | LL | / match x { LL | | FOO_C => println!(), LL | | _ => (), LL | | } | |_____^ help: try this: `if x == FOO_C { println!() }` error: you seem to be trying to use `match` for an equality check. Consider using `if` --> $DIR/single_match.rs:111:5 | LL | / match &&x { LL | | Foo::A => println!(), LL | | _ => (), LL | | } | |_____^ help: try this: `if x == Foo::A { println!() }` error: you seem to be trying to use `match` for an equality check. Consider using `if` --> $DIR/single_match.rs:117:5 | LL | / match &x { LL | | Foo::A => println!(), LL | | _ => (), LL | | } | |_____^ help: try this: `if x == &Foo::A { println!() }` error: you seem to be trying to use `match` for destructuring a single pattern. Consider using `if let` --> $DIR/single_match.rs:134:5 | LL | / match x { LL | | Bar::A => println!(), LL | | _ => (), LL | | } | |_____^ help: try this: `if let Bar::A = x { println!() }` error: aborting due to 12 previous errors