3 void eqnbox(int p1, int p2, int lu)
10 b = max(ebase[p1], ebase[p2]);
11 eht[yyval] = h = b + max(eht[p1]-ebase[p1],
14 dprintf(".\tS%d <- %d %d; b=%g, h=%g\n", yyval, p1, p2, b, h);
15 sh = pad(class[rclass[p1]][lclass[p2]]);
17 printf(".nr %d \\w'\\*(%d%s'\n", p1, p1, sh);
18 printf(".ds %d \\h'|\\n(09u-\\n(%du'\\*(%d\n", p1, p1, p1);
20 printf(".as %d \"%s\\*(%d\n", yyval, sh, p2);
21 rfont[p1] = rfont[p2];
22 rclass[p1] = rclass[p2];